Base | Representation |
---|---|
bin | 100111111000010100110… |
… | …1010000101010010010101 |
3 | 201101222121200200100002102 |
4 | 1033300221222011102111 |
5 | 1204300221223323003 |
6 | 15353545545451445 |
7 | 1103665126133102 |
oct | 117605152052225 |
9 | 21358550610072 |
10 | 5481077167253 |
11 | 182356a195706 |
12 | 7463297a0b85 |
13 | 309b2ba5248c |
14 | 14d3dd79baa9 |
15 | 97896e5e588 |
hex | 4fc29a85495 |
5481077167253 has 2 divisors, whose sum is σ = 5481077167254. Its totient is φ = 5481077167252.
The previous prime is 5481077167207. The next prime is 5481077167283. The reversal of 5481077167253 is 3527617701845.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3404198432209 + 2076878735044 = 1845047^2 + 1441138^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5481077167253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5481077167283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2740538583626 + 2740538583627.
It is an arithmetic number, because the mean of its divisors is an integer number (2740538583627).
Almost surely, 25481077167253 is an apocalyptic number.
It is an amenable number.
5481077167253 is a deficient number, since it is larger than the sum of its proper divisors (1).
5481077167253 is an equidigital number, since it uses as much as digits as its factorization.
5481077167253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9878400, while the sum is 56.
The spelling of 5481077167253 in words is "five trillion, four hundred eighty-one billion, seventy-seven million, one hundred sixty-seven thousand, two hundred fifty-three".
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