Base | Representation |
---|---|
bin | 11000111100101000110011… |
… | …11101111010001110110111 |
3 | 21012020120101102011201012012 |
4 | 30132110121331322032313 |
5 | 24142311342022302021 |
6 | 312402205502314435 |
7 | 14361336152631242 |
oct | 1436243175721667 |
9 | 235216342151165 |
10 | 54860052931511 |
11 | 16531021754763 |
12 | 61a02b4888a1b |
13 | 247c385b98a79 |
14 | d793527c0259 |
15 | 65208111835b |
hex | 31e519f7a3b7 |
54860052931511 has 2 divisors, whose sum is σ = 54860052931512. Its totient is φ = 54860052931510.
The previous prime is 54860052931507. The next prime is 54860052931529. The reversal of 54860052931511 is 11513925006845.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54860052931511 - 22 = 54860052931507 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54860052931511.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54860052951511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27430026465755 + 27430026465756.
It is an arithmetic number, because the mean of its divisors is an integer number (27430026465756).
Almost surely, 254860052931511 is an apocalyptic number.
54860052931511 is a deficient number, since it is larger than the sum of its proper divisors (1).
54860052931511 is an equidigital number, since it uses as much as digits as its factorization.
54860052931511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296000, while the sum is 50.
The spelling of 54860052931511 in words is "fifty-four trillion, eight hundred sixty billion, fifty-two million, nine hundred thirty-one thousand, five hundred eleven".
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