Base | Representation |
---|---|
bin | 110011001000000001… |
… | …010011100000011001 |
3 | 12020200202100220002001 |
4 | 303020001103200121 |
5 | 1344411210032133 |
6 | 41115114441001 |
7 | 3652234065643 |
oct | 631001234031 |
9 | 166622326061 |
10 | 54895392793 |
11 | 2131002211a |
12 | a780433161 |
13 | 523b033a57 |
14 | 292a961893 |
15 | 166453687d |
hex | cc8053819 |
54895392793 has 2 divisors, whose sum is σ = 54895392794. Its totient is φ = 54895392792.
The previous prime is 54895392719. The next prime is 54895392821. The reversal of 54895392793 is 39729359845.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54687225609 + 208167184 = 233853^2 + 14428^2 .
It is a cyclic number.
It is not a de Polignac number, because 54895392793 - 29 = 54895392281 is a prime.
It is not a weakly prime, because it can be changed into another prime (54895392593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27447696396 + 27447696397.
It is an arithmetic number, because the mean of its divisors is an integer number (27447696397).
Almost surely, 254895392793 is an apocalyptic number.
It is an amenable number.
54895392793 is a deficient number, since it is larger than the sum of its proper divisors (1).
54895392793 is an equidigital number, since it uses as much as digits as its factorization.
54895392793 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 73483200, while the sum is 64.
The spelling of 54895392793 in words is "fifty-four billion, eight hundred ninety-five million, three hundred ninety-two thousand, seven hundred ninety-three".
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