Base | Representation |
---|---|
bin | 110011001000110011… |
… | …111110100000000111 |
3 | 12020201200100202100111 |
4 | 303020303332200013 |
5 | 1344423110113403 |
6 | 41120311253451 |
7 | 3652455021541 |
oct | 631063764007 |
9 | 166650322314 |
10 | 54908676103 |
11 | 21317575066 |
12 | a78497a287 |
13 | 5240a04bb8 |
14 | 292c61c691 |
15 | 16657ac56d |
hex | cc8cfe807 |
54908676103 has 2 divisors, whose sum is σ = 54908676104. Its totient is φ = 54908676102.
The previous prime is 54908676083. The next prime is 54908676169. The reversal of 54908676103 is 30167680945.
54908676103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54908676103 - 25 = 54908676071 is a prime.
It is a super-2 number, since 2×549086761032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54908676803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27454338051 + 27454338052.
It is an arithmetic number, because the mean of its divisors is an integer number (27454338052).
Almost surely, 254908676103 is an apocalyptic number.
54908676103 is a deficient number, since it is larger than the sum of its proper divisors (1).
54908676103 is an equidigital number, since it uses as much as digits as its factorization.
54908676103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 49.
The spelling of 54908676103 in words is "fifty-four billion, nine hundred eight million, six hundred seventy-six thousand, one hundred three".
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