Base | Representation |
---|---|
bin | 110011001100011001… |
… | …110110001110000111 |
3 | 12020212212202020102201 |
4 | 303030121312032013 |
5 | 1400034021412203 |
6 | 41130303015331 |
7 | 3654116145412 |
oct | 631431661607 |
9 | 166785666381 |
10 | 54968935303 |
11 | 21348592757 |
12 | a7a0b9a547 |
13 | 5250342b29 |
14 | 2936626b79 |
15 | 166ac11e1d |
hex | ccc676387 |
54968935303 has 2 divisors, whose sum is σ = 54968935304. Its totient is φ = 54968935302.
The previous prime is 54968935247. The next prime is 54968935309. The reversal of 54968935303 is 30353986945.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54968935303 - 29 = 54968934791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54968935309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27484467651 + 27484467652.
It is an arithmetic number, because the mean of its divisors is an integer number (27484467652).
Almost surely, 254968935303 is an apocalyptic number.
54968935303 is a deficient number, since it is larger than the sum of its proper divisors (1).
54968935303 is an equidigital number, since it uses as much as digits as its factorization.
54968935303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10497600, while the sum is 55.
The spelling of 54968935303 in words is "fifty-four billion, nine hundred sixty-eight million, nine hundred thirty-five thousand, three hundred three".
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