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5500140433 is a prime number
BaseRepresentation
bin1010001111101010…
…10111101110010001
3112012022111002020221
411013311113232101
542231013443213
62305435033041
7253204264564
oct50765275621
915168432227
105500140433
11237275aa07
121095b9b781
13698662888
143a26924db
15222ceb38d
hex147d57b91

5500140433 has 2 divisors, whose sum is σ = 5500140434. Its totient is φ = 5500140432.

The previous prime is 5500140427. The next prime is 5500140467. The reversal of 5500140433 is 3340410055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5116254784 + 383885649 = 71528^2 + 19593^2 .

It is a cyclic number.

It is not a de Polignac number, because 5500140433 - 29 = 5500139921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5500140398 and 5500140407.

It is not a weakly prime, because it can be changed into another prime (5500140403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750070216 + 2750070217.

It is an arithmetic number, because the mean of its divisors is an integer number (2750070217).

Almost surely, 25500140433 is an apocalyptic number.

It is an amenable number.

5500140433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5500140433 is an equidigital number, since it uses as much as digits as its factorization.

5500140433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 25.

The square root of 5500140433 is about 74162.9316640058. The cubic root of 5500140433 is about 1765.1891910930.

Adding to 5500140433 its reverse (3340410055), we get a palindrome (8840550488).

The spelling of 5500140433 in words is "five billion, five hundred million, one hundred forty thousand, four hundred thirty-three".