Base | Representation |
---|---|
bin | 10000000000100001110… |
… | …01100110010001001111 |
3 | 1221120202012001222120221 |
4 | 20000100321212101033 |
5 | 33002440033121203 |
6 | 1100403512052211 |
7 | 54511326214234 |
oct | 10002071462117 |
9 | 1846665058527 |
10 | 550039348303 |
11 | 1a22a7966505 |
12 | 8a727094067 |
13 | 3cb3a0b6803 |
14 | 1c89cc7778b |
15 | e493b9babd |
hex | 8010e6644f |
550039348303 has 2 divisors, whose sum is σ = 550039348304. Its totient is φ = 550039348302.
The previous prime is 550039348267. The next prime is 550039348319. The reversal of 550039348303 is 303843930055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 550039348303 - 237 = 412600394831 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 550039348303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550039348393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275019674151 + 275019674152.
It is an arithmetic number, because the mean of its divisors is an integer number (275019674152).
Almost surely, 2550039348303 is an apocalyptic number.
550039348303 is a deficient number, since it is larger than the sum of its proper divisors (1).
550039348303 is an equidigital number, since it uses as much as digits as its factorization.
550039348303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 583200, while the sum is 43.
The spelling of 550039348303 in words is "five hundred fifty billion, thirty-nine million, three hundred forty-eight thousand, three hundred three".
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