Base | Representation |
---|---|
bin | 10000000000100011000… |
… | …00010111101000111101 |
3 | 1221120202220012100120001 |
4 | 20000101200113220331 |
5 | 33003000133340442 |
6 | 1100404513554301 |
7 | 54511511465056 |
oct | 10002140275075 |
9 | 1846686170501 |
10 | 550049511997 |
11 | 1a2302678657 |
12 | 8a72a575991 |
13 | 3cb3c234a2b |
14 | 1c8a036172d |
15 | e494a082b7 |
hex | 8011817a3d |
550049511997 has 2 divisors, whose sum is σ = 550049511998. Its totient is φ = 550049511996.
The previous prime is 550049511971. The next prime is 550049512009. The reversal of 550049511997 is 799115940055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 545107562596 + 4941949401 = 738314^2 + 70299^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-550049511997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550049515997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275024755998 + 275024755999.
It is an arithmetic number, because the mean of its divisors is an integer number (275024755999).
Almost surely, 2550049511997 is an apocalyptic number.
It is an amenable number.
550049511997 is a deficient number, since it is larger than the sum of its proper divisors (1).
550049511997 is an equidigital number, since it uses as much as digits as its factorization.
550049511997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2551500, while the sum is 55.
The spelling of 550049511997 in words is "five hundred fifty billion, forty-nine million, five hundred eleven thousand, nine hundred ninety-seven".
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