Base | Representation |
---|---|
bin | 101000000001011001010… |
… | …1010001111000011101001 |
3 | 201110211220011200221220122 |
4 | 1100002302222033003221 |
5 | 1210110114210230144 |
6 | 15410530443133025 |
7 | 1105254615530522 |
oct | 120026252170351 |
9 | 21424804627818 |
10 | 5500555555049 |
11 | 1830855236765 |
12 | 74a064b14175 |
13 | 30b914348b29 |
14 | 15032a6a3849 |
15 | 98136ee37ee |
hex | 500b2a8f0e9 |
5500555555049 has 2 divisors, whose sum is σ = 5500555555050. Its totient is φ = 5500555555048.
The previous prime is 5500555555037. The next prime is 5500555555091. The reversal of 5500555555049 is 9405555550055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3437712767449 + 2062842787600 = 1854107^2 + 1436260^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5500555555049 is a prime.
It is a super-2 number, since 2×55005555550492 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5500555555009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750277777524 + 2750277777525.
It is an arithmetic number, because the mean of its divisors is an integer number (2750277777525).
Almost surely, 25500555555049 is an apocalyptic number.
It is an amenable number.
5500555555049 is a deficient number, since it is larger than the sum of its proper divisors (1).
5500555555049 is an equidigital number, since it uses as much as digits as its factorization.
5500555555049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14062500, while the sum is 53.
The spelling of 5500555555049 in words is "five trillion, five hundred billion, five hundred fifty-five million, five hundred fifty-five thousand, forty-nine".
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