Base | Representation |
---|---|
bin | 11001000001000001000001… |
… | …10011000010100001000011 |
3 | 21012202221200201122121012122 |
4 | 30200200200303002201003 |
5 | 24202242441243041411 |
6 | 312555245412314455 |
7 | 14405243154421331 |
oct | 1440404063024103 |
9 | 235687621577178 |
10 | 55010491377731 |
11 | 16589900297a5a |
12 | 620549a312a2b |
13 | 249060c22b056 |
14 | d827444a2b51 |
15 | 655e384529db |
hex | 320820cc2843 |
55010491377731 has 2 divisors, whose sum is σ = 55010491377732. Its totient is φ = 55010491377730.
The previous prime is 55010491377727. The next prime is 55010491377791. The reversal of 55010491377731 is 13777319401055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55010491377731 - 22 = 55010491377727 is a prime.
It is a super-2 number, since 2×550104913777312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55010491377791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505245688865 + 27505245688866.
It is an arithmetic number, because the mean of its divisors is an integer number (27505245688866).
Almost surely, 255010491377731 is an apocalyptic number.
55010491377731 is a deficient number, since it is larger than the sum of its proper divisors (1).
55010491377731 is an equidigital number, since it uses as much as digits as its factorization.
55010491377731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2778300, while the sum is 53.
The spelling of 55010491377731 in words is "fifty-five trillion, ten billion, four hundred ninety-one million, three hundred seventy-seven thousand, seven hundred thirty-one".
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