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55011000133 is a prime number
BaseRepresentation
bin110011001110111010…
…010011111101000101
312020222210220100112101
4303032322103331011
51400130304001013
641134404352101
73655136533405
oct631672237505
9166883810471
1055011000133
112136a303681
12a7b30a5631
135258c8046b
14293c056805
15166e7708dd
hexccee93f45

55011000133 has 2 divisors, whose sum is σ = 55011000134. Its totient is φ = 55011000132.

The previous prime is 55011000049. The next prime is 55011000157. The reversal of 55011000133 is 33100011055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46043288929 + 8967711204 = 214577^2 + 94698^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55011000133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 55011000133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55011000173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505500066 + 27505500067.

It is an arithmetic number, because the mean of its divisors is an integer number (27505500067).

Almost surely, 255011000133 is an apocalyptic number.

It is an amenable number.

55011000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

55011000133 is an equidigital number, since it uses as much as digits as its factorization.

55011000133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 225, while the sum is 19.

Adding to 55011000133 its reverse (33100011055), we get a palindrome (88111011188).

The spelling of 55011000133 in words is "fifty-five billion, eleven million, one hundred thirty-three", and thus it is an aban number.