Base | Representation |
---|---|
bin | 10000000000101100111… |
… | …10111001011010101111 |
3 | 1221120222201022121020001 |
4 | 20000112132321122233 |
5 | 33003133022342033 |
6 | 1100421055405131 |
7 | 54513544306531 |
oct | 10002636713257 |
9 | 1846881277201 |
10 | 550133012143 |
11 | 1a234581a540 |
12 | 8a7525237a7 |
13 | 3cb5361c2c0 |
14 | 1c8ab499851 |
15 | e49beede7d |
hex | 80167b96af |
550133012143 has 32 divisors (see below), whose sum is σ = 669835252800. Its totient is φ = 444905395200.
The previous prime is 550133012141. The next prime is 550133012347. The reversal of 550133012143 is 341210331055.
It is a happy number.
550133012143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 550133012143 - 21 = 550133012141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (550133012141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2120923 + ... + 2366131.
It is an arithmetic number, because the mean of its divisors is an integer number (20932351650).
Almost surely, 2550133012143 is an apocalyptic number.
550133012143 is a deficient number, since it is larger than the sum of its proper divisors (119702240657).
550133012143 is a wasteful number, since it uses less digits than its factorization.
550133012143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 245803.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 550133012143 its reverse (341210331055), we get a palindrome (891343343198).
The spelling of 550133012143 in words is "five hundred fifty billion, one hundred thirty-three million, twelve thousand, one hundred forty-three".
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