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55015003993 is a prime number
BaseRepresentation
bin110011001111001001…
…100101011101011001
312021000002102202210111
4303033021211131121
51400132320111433
641135030244321
73655215550435
oct631711453531
9167002382714
1055015003993
1121371598854
12a7b44b66a1
135259a52a01
14293c7b99c5
15166ecb1dcd
hexccf265759

55015003993 has 2 divisors, whose sum is σ = 55015003994. Its totient is φ = 55015003992.

The previous prime is 55015003973. The next prime is 55015004003. The reversal of 55015003993 is 39930051055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51385182489 + 3629821504 = 226683^2 + 60248^2 .

It is a cyclic number.

It is not a de Polignac number, because 55015003993 - 25 = 55015003961 is a prime.

It is not a weakly prime, because it can be changed into another prime (55015003913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27507501996 + 27507501997.

It is an arithmetic number, because the mean of its divisors is an integer number (27507501997).

Almost surely, 255015003993 is an apocalyptic number.

It is an amenable number.

55015003993 is a deficient number, since it is larger than the sum of its proper divisors (1).

55015003993 is an equidigital number, since it uses as much as digits as its factorization.

55015003993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 91125, while the sum is 40.

The spelling of 55015003993 in words is "fifty-five billion, fifteen million, three thousand, nine hundred ninety-three".