Base | Representation |
---|---|
bin | 110011001111001001… |
… | …100101011101100011 |
3 | 12021000002102202210212 |
4 | 303033021211131203 |
5 | 1400132320112003 |
6 | 41135030244335 |
7 | 3655215550451 |
oct | 631711453543 |
9 | 167002382725 |
10 | 55015004003 |
11 | 21371598863 |
12 | a7b44b66ab |
13 | 5259a52a0b |
14 | 293c7b99d1 |
15 | 166ecb1dd8 |
hex | ccf265763 |
55015004003 has 2 divisors, whose sum is σ = 55015004004. Its totient is φ = 55015004002.
The previous prime is 55015003993. The next prime is 55015004041. The reversal of 55015004003 is 30040051055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55015004003 - 234 = 37835134819 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55015004003.
It is not a weakly prime, because it can be changed into another prime (55015000003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27507502001 + 27507502002.
It is an arithmetic number, because the mean of its divisors is an integer number (27507502002).
Almost surely, 255015004003 is an apocalyptic number.
55015004003 is a deficient number, since it is larger than the sum of its proper divisors (1).
55015004003 is an equidigital number, since it uses as much as digits as its factorization.
55015004003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 23.
Adding to 55015004003 its reverse (30040051055), we get a palindrome (85055055058).
The spelling of 55015004003 in words is "fifty-five billion, fifteen million, four thousand, three".
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