Base | Representation |
---|---|
bin | 10000000001000110001… |
… | …01000110100101000001 |
3 | 1221121112102222212220102 |
4 | 20000203011012211001 |
5 | 33004101123312423 |
6 | 1100454045252145 |
7 | 54522021553061 |
oct | 10004305064501 |
9 | 1847472885812 |
10 | 550344354113 |
11 | 1a2444049924 |
12 | 8a7b1264055 |
13 | 3cb88347c18 |
14 | 1c8cb5913a1 |
15 | e4b0848c28 |
hex | 8023146941 |
550344354113 has 2 divisors, whose sum is σ = 550344354114. Its totient is φ = 550344354112.
The previous prime is 550344354067. The next prime is 550344354227. The reversal of 550344354113 is 311453443055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 358120858624 + 192223495489 = 598432^2 + 438433^2 .
It is a cyclic number.
It is not a de Polignac number, because 550344354113 - 28 = 550344353857 is a prime.
It is not a weakly prime, because it can be changed into another prime (550344350113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275172177056 + 275172177057.
It is an arithmetic number, because the mean of its divisors is an integer number (275172177057).
Almost surely, 2550344354113 is an apocalyptic number.
It is an amenable number.
550344354113 is a deficient number, since it is larger than the sum of its proper divisors (1).
550344354113 is an equidigital number, since it uses as much as digits as its factorization.
550344354113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 550344354113 its reverse (311453443055), we get a palindrome (861797797168).
The spelling of 550344354113 in words is "five hundred fifty billion, three hundred forty-four million, three hundred fifty-four thousand, one hundred thirteen".
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