Base | Representation |
---|---|
bin | 11001000001111110100101… |
… | …11000111100011110111111 |
3 | 21012220010000020001212220101 |
4 | 30200333102320330132333 |
5 | 24203313134233311112 |
6 | 313022353253501531 |
7 | 14410523222423305 |
oct | 1440772270743677 |
9 | 235803006055811 |
10 | 55043544041407 |
11 | 165a19216a1429 |
12 | 620b9836418a7 |
13 | 2493778b862cc |
14 | d8419c102275 |
15 | 656c20074757 |
hex | 320fd2e3c7bf |
55043544041407 has 2 divisors, whose sum is σ = 55043544041408. Its totient is φ = 55043544041406.
The previous prime is 55043544041393. The next prime is 55043544041449. The reversal of 55043544041407 is 70414044534055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55043544041407 - 239 = 54493788227519 is a prime.
It is a super-3 number, since 3×550435440414073 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55043544047407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27521772020703 + 27521772020704.
It is an arithmetic number, because the mean of its divisors is an integer number (27521772020704).
Almost surely, 255043544041407 is an apocalyptic number.
55043544041407 is a deficient number, since it is larger than the sum of its proper divisors (1).
55043544041407 is an equidigital number, since it uses as much as digits as its factorization.
55043544041407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688000, while the sum is 46.
The spelling of 55043544041407 in words is "fifty-five trillion, forty-three billion, five hundred forty-four million, forty-one thousand, four hundred seven".
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