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55046405863331 is a prime number
BaseRepresentation
bin11001000010000011111010…
…11101111011011110100011
321012220101101200002111112222
430201001331131323132203
524203340014400111311
6313023545244341255
714410654152464411
oct1441017535733643
9235811350074488
1055046405863331
11165a3060064613
126210441b4482b
132493b13a4a86c
14d8439021a2b1
15656d3b421adb
hex32107d77b7a3

55046405863331 has 2 divisors, whose sum is σ = 55046405863332. Its totient is φ = 55046405863330.

The previous prime is 55046405863313. The next prime is 55046405863399. The reversal of 55046405863331 is 13336850464055.

Together with previous prime (55046405863313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55046405863331 is a prime.

It is a super-2 number, since 2×550464058633312 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (55046405863231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27523202931665 + 27523202931666.

It is an arithmetic number, because the mean of its divisors is an integer number (27523202931666).

Almost surely, 255046405863331 is an apocalyptic number.

55046405863331 is a deficient number, since it is larger than the sum of its proper divisors (1).

55046405863331 is an equidigital number, since it uses as much as digits as its factorization.

55046405863331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552000, while the sum is 53.

The spelling of 55046405863331 in words is "fifty-five trillion, forty-six billion, four hundred five million, eight hundred sixty-three thousand, three hundred thirty-one".