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550498074437 is a prime number
BaseRepresentation
bin10000000001011000011…
…11011111111101000101
31221121221011020200112202
420000230033133331011
533004410001340222
61100521220124245
754525566266223
oct10005417377505
91847834220482
10550498074437
111a25128a2213
128a834836685
133cbb114a2ac
141c903b67b13
15e4be0b0892
hex802c3dff45

550498074437 has 2 divisors, whose sum is σ = 550498074438. Its totient is φ = 550498074436.

The previous prime is 550498074337. The next prime is 550498074487. The reversal of 550498074437 is 734470894055.

550498074437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 530451479041 + 20046595396 = 728321^2 + 141586^2 .

It is a cyclic number.

It is not a de Polignac number, because 550498074437 - 212 = 550498070341 is a prime.

It is a super-3 number, since 3×5504980744373 (a number of 36 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (550498074487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275249037218 + 275249037219.

It is an arithmetic number, because the mean of its divisors is an integer number (275249037219).

Almost surely, 2550498074437 is an apocalyptic number.

It is an amenable number.

550498074437 is a deficient number, since it is larger than the sum of its proper divisors (1).

550498074437 is an equidigital number, since it uses as much as digits as its factorization.

550498074437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16934400, while the sum is 56.

The spelling of 550498074437 in words is "five hundred fifty billion, four hundred ninety-eight million, seventy-four thousand, four hundred thirty-seven".