Base | Representation |
---|---|
bin | 101000000011100000110… |
… | …0110001001111100011111 |
3 | 201111021121221222010112101 |
4 | 1100013001212021330133 |
5 | 1210143421341023241 |
6 | 15413001502145531 |
7 | 1105505352236452 |
oct | 120070146117437 |
9 | 21437557863471 |
10 | 5505101111071 |
11 | 1832778072231 |
12 | 74ab132822a7 |
13 | 30c189cb3053 |
14 | 15063c26b499 |
15 | 983010cee31 |
hex | 501c1989f1f |
5505101111071 has 4 divisors (see below), whose sum is σ = 5505576232792. Its totient is φ = 5504625989352.
The previous prime is 5505101111009. The next prime is 5505101111099. The reversal of 5505101111071 is 1701111015055.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5505101111071 is a prime.
It is a super-3 number, since 3×55051011110713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5505101151071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 237543480 + ... + 237566653.
It is an arithmetic number, because the mean of its divisors is an integer number (1376394058198).
Almost surely, 25505101111071 is an apocalyptic number.
5505101111071 is a deficient number, since it is larger than the sum of its proper divisors (475121721).
5505101111071 is a wasteful number, since it uses less digits than its factorization.
5505101111071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 475121720.
The product of its (nonzero) digits is 875, while the sum is 28.
The spelling of 5505101111071 in words is "five trillion, five hundred five billion, one hundred one million, one hundred eleven thousand, seventy-one".
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