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55051314224279 is a prime number
BaseRepresentation
bin11001000010001101000100…
…00001110101110010010111
321012220212001202001001222012
430201012202001311302113
524203430042420134104
6313030120303454435
714411216613041552
oct1441064201656227
9235825052031865
1055051314224279
11165a514977086a
1262113918b741b
132494416902459
14d846d8065699
156570272c5d6e
hex3211a2075c97

55051314224279 has 2 divisors, whose sum is σ = 55051314224280. Its totient is φ = 55051314224278.

The previous prime is 55051314224237. The next prime is 55051314224297. The reversal of 55051314224279 is 97242241315055.

Together with next prime (55051314224297) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55051314224279 is a prime.

It is a super-3 number, since 3×550513142242793 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55051314224209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27525657112139 + 27525657112140.

It is an arithmetic number, because the mean of its divisors is an integer number (27525657112140).

Almost surely, 255051314224279 is an apocalyptic number.

55051314224279 is a deficient number, since it is larger than the sum of its proper divisors (1).

55051314224279 is an equidigital number, since it uses as much as digits as its factorization.

55051314224279 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024000, while the sum is 50.

The spelling of 55051314224279 in words is "fifty-five trillion, fifty-one billion, three hundred fourteen million, two hundred twenty-four thousand, two hundred seventy-nine".