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5505498785573 is a prime number
BaseRepresentation
bin101000000011101100101…
…0011001010011100100101
3201111022122200021002101122
41100013121103022130211
51210200230142114243
615413105145503325
71105521251354363
oct120073123123445
921438580232348
105505498785573
111832961599a46
1274b0044a1b45
1330c2214bbcc7
14150678dc8633
1598325e84668
hex501d94ca725

5505498785573 has 2 divisors, whose sum is σ = 5505498785574. Its totient is φ = 5505498785572.

The previous prime is 5505498785543. The next prime is 5505498785587. The reversal of 5505498785573 is 3755878945055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5493595320964 + 11903464609 = 2343842^2 + 109103^2 .

It is a cyclic number.

It is not a de Polignac number, because 5505498785573 - 212 = 5505498781477 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5505498785497 and 5505498785506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5505498785513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2752749392786 + 2752749392787.

It is an arithmetic number, because the mean of its divisors is an integer number (2752749392787).

Almost surely, 25505498785573 is an apocalyptic number.

It is an amenable number.

5505498785573 is a deficient number, since it is larger than the sum of its proper divisors (1).

5505498785573 is an equidigital number, since it uses as much as digits as its factorization.

5505498785573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1058400000, while the sum is 71.

The spelling of 5505498785573 in words is "five trillion, five hundred five billion, four hundred ninety-eight million, seven hundred eighty-five thousand, five hundred seventy-three".