Base | Representation |
---|---|
bin | 10000000001100100110… |
… | …00011110000001011101 |
3 | 1221122012100002101010021 |
4 | 20000302120132001131 |
5 | 33010112334322432 |
6 | 1100535340112141 |
7 | 54531260015452 |
oct | 10006230360135 |
9 | 1848170071107 |
10 | 550601089117 |
11 | 1a2565a62712 |
12 | 8a863235651 |
13 | 3cbc95a8021 |
14 | 1c913701829 |
15 | e4c815d697 |
hex | 803261e05d |
550601089117 has 2 divisors, whose sum is σ = 550601089118. Its totient is φ = 550601089116.
The previous prime is 550601089061. The next prime is 550601089121. The reversal of 550601089117 is 711980106055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 430875400921 + 119725688196 = 656411^2 + 346014^2 .
It is a cyclic number.
It is not a de Polignac number, because 550601089117 - 223 = 550592700509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550601089187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275300544558 + 275300544559.
It is an arithmetic number, because the mean of its divisors is an integer number (275300544559).
Almost surely, 2550601089117 is an apocalyptic number.
It is an amenable number.
550601089117 is a deficient number, since it is larger than the sum of its proper divisors (1).
550601089117 is an equidigital number, since it uses as much as digits as its factorization.
550601089117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75600, while the sum is 43.
The spelling of 550601089117 in words is "five hundred fifty billion, six hundred one million, eighty-nine thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •