Base | Representation |
---|---|
bin | 11001000010011110010111… |
… | …00000011101000101011101 |
3 | 21012221202000212221220011211 |
4 | 30201033023200131011131 |
5 | 24204103102103100023 |
6 | 313034253535144421 |
7 | 14411665666206025 |
oct | 1441171340350535 |
9 | 235852025856154 |
10 | 55060600050013 |
11 | 165a9084335108 |
12 | 6213143675111 |
13 | 24952666599ac |
14 | d84d39400a85 |
15 | 6573bc611a0d |
hex | 3213cb81d15d |
55060600050013 has 2 divisors, whose sum is σ = 55060600050014. Its totient is φ = 55060600050012.
The previous prime is 55060600049989. The next prime is 55060600050019. The reversal of 55060600050013 is 31005000606055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52102382367204 + 2958217682809 = 7218198^2 + 1719947^2 .
It is a cyclic number.
It is not a de Polignac number, because 55060600050013 - 221 = 55060597952861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55060600050019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27530300025006 + 27530300025007.
It is an arithmetic number, because the mean of its divisors is an integer number (27530300025007).
Almost surely, 255060600050013 is an apocalyptic number.
It is an amenable number.
55060600050013 is a deficient number, since it is larger than the sum of its proper divisors (1).
55060600050013 is an equidigital number, since it uses as much as digits as its factorization.
55060600050013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 55060600050013 its reverse (31005000606055), we get a palindrome (86065600656068).
The spelling of 55060600050013 in words is "fifty-five trillion, sixty billion, six hundred million, fifty thousand, thirteen".
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