Base | Representation |
---|---|
bin | 11001000010100011000100… |
… | …11111101111110011001111 |
3 | 21012221222120102120110210220 |
4 | 30201101202133233303033 |
5 | 24204123244101133033 |
6 | 313035353150002423 |
7 | 14412115525633242 |
oct | 1441214237576317 |
9 | 235858512513726 |
10 | 55063133224143 |
11 | 165aa164237350 |
12 | 621372baa6413 |
13 | 249557b402ab5 |
14 | d850d9a09259 |
15 | 6574b9be1bb3 |
hex | 3214627efccf |
55063133224143 has 64 divisors (see below), whose sum is σ = 84901117593600. Its totient is φ = 31432938992000.
The previous prime is 55063133224139. The next prime is 55063133224159. The reversal of 55063133224143 is 34142233136055.
It is not a de Polignac number, because 55063133224143 - 22 = 55063133224139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55063133224095 and 55063133224104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55063133224193) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3674488 + ... + 11118818.
It is an arithmetic number, because the mean of its divisors is an integer number (1326579962400).
Almost surely, 255063133224143 is an apocalyptic number.
55063133224143 is a deficient number, since it is larger than the sum of its proper divisors (29837984369457).
55063133224143 is a wasteful number, since it uses less digits than its factorization.
55063133224143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7444564.
The product of its (nonzero) digits is 777600, while the sum is 42.
The spelling of 55063133224143 in words is "fifty-five trillion, sixty-three billion, one hundred thirty-three million, two hundred twenty-four thousand, one hundred forty-three".
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