Base | Representation |
---|---|
bin | 10000000010001101111… |
… | …11100100111101011111 |
3 | 1221200002102202122112122 |
4 | 20001012333210331133 |
5 | 33011314400313341 |
6 | 1101033531453155 |
7 | 54542656154213 |
oct | 10010677447537 |
9 | 1850072678478 |
10 | 550946885471 |
11 | 1a2723176624 |
12 | 8a93abb71bb |
13 | 3cc5311ba58 |
14 | 1c9475d6943 |
15 | e4e86b694b |
hex | 8046fe4f5f |
550946885471 has 2 divisors, whose sum is σ = 550946885472. Its totient is φ = 550946885470.
The previous prime is 550946885449. The next prime is 550946885483. The reversal of 550946885471 is 174588649055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 550946885471 - 218 = 550946623327 is a prime.
It is a super-3 number, since 3×5509468854713 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550946885171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275473442735 + 275473442736.
It is an arithmetic number, because the mean of its divisors is an integer number (275473442736).
Almost surely, 2550946885471 is an apocalyptic number.
550946885471 is a deficient number, since it is larger than the sum of its proper divisors (1).
550946885471 is an equidigital number, since it uses as much as digits as its factorization.
550946885471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384000, while the sum is 62.
The spelling of 550946885471 in words is "five hundred fifty billion, nine hundred forty-six million, eight hundred eighty-five thousand, four hundred seventy-one".
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