Base | Representation |
---|---|
bin | 110011010100000001… |
… | …101111100100100111 |
3 | 12021012210102011221012 |
4 | 303110001233210213 |
5 | 1400314242144333 |
6 | 41151112212435 |
7 | 3660231236045 |
oct | 632401574447 |
9 | 167183364835 |
10 | 55096834343 |
11 | 214037aa141 |
12 | a81799a11b |
13 | 52709a4235 |
14 | 29495db395 |
15 | 1677077e48 |
hex | cd406f927 |
55096834343 has 2 divisors, whose sum is σ = 55096834344. Its totient is φ = 55096834342.
The previous prime is 55096834333. The next prime is 55096834361. The reversal of 55096834343 is 34343869055.
55096834343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55096834343 - 24 = 55096834327 is a prime.
It is a super-2 number, since 2×550968343432 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55096834291 and 55096834300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55096834333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27548417171 + 27548417172.
It is an arithmetic number, because the mean of its divisors is an integer number (27548417172).
Almost surely, 255096834343 is an apocalyptic number.
55096834343 is a deficient number, since it is larger than the sum of its proper divisors (1).
55096834343 is an equidigital number, since it uses as much as digits as its factorization.
55096834343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4665600, while the sum is 50.
The spelling of 55096834343 in words is "fifty-five billion, ninety-six million, eight hundred thirty-four thousand, three hundred forty-three".
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