Base | Representation |
---|---|
bin | 100000110101111… |
… | …000000010000011 |
3 | 1102101210101202002 |
4 | 200311320002003 |
5 | 2112023302201 |
6 | 130401414215 |
7 | 16440241436 |
oct | 4065700203 |
9 | 1371711662 |
10 | 550994051 |
11 | 263026a93 |
12 | 13463a36b |
13 | 8a1caaaa |
14 | 5326b81d |
15 | 3358c76b |
hex | 20d78083 |
550994051 has 2 divisors, whose sum is σ = 550994052. Its totient is φ = 550994050.
The previous prime is 550994023. The next prime is 550994063. The reversal of 550994051 is 150499055.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-550994051 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 550993996 and 550994014.
It is not a weakly prime, because it can be changed into another prime (550994011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275497025 + 275497026.
It is an arithmetic number, because the mean of its divisors is an integer number (275497026).
Almost surely, 2550994051 is an apocalyptic number.
550994051 is a deficient number, since it is larger than the sum of its proper divisors (1).
550994051 is an equidigital number, since it uses as much as digits as its factorization.
550994051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40500, while the sum is 38.
The square root of 550994051 is about 23473.2624703086. The cubic root of 550994051 is about 819.8145778446.
The spelling of 550994051 in words is "five hundred fifty million, nine hundred ninety-four thousand, fifty-one".
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