Base | Representation |
---|---|
bin | 101000000101110010111… |
… | …1000111100011110011111 |
3 | 201111202021201110200010222 |
4 | 1100023211320330132133 |
5 | 1210233442233434321 |
6 | 15415132241151555 |
7 | 1106041026411314 |
oct | 120134570743637 |
9 | 21452251420128 |
10 | 5510004983711 |
11 | 1834864193338 |
12 | 74ba6162b5bb |
13 | 30c78bc55a37 |
14 | 150985668d0b |
15 | 984db8993ab |
hex | 502e5e3c79f |
5510004983711 has 2 divisors, whose sum is σ = 5510004983712. Its totient is φ = 5510004983710.
The previous prime is 5510004983687. The next prime is 5510004983753. The reversal of 5510004983711 is 1173894000155.
5510004983711 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5510004983711 - 210 = 5510004982687 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5510204983711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2755002491855 + 2755002491856.
It is an arithmetic number, because the mean of its divisors is an integer number (2755002491856).
Almost surely, 25510004983711 is an apocalyptic number.
5510004983711 is a deficient number, since it is larger than the sum of its proper divisors (1).
5510004983711 is an equidigital number, since it uses as much as digits as its factorization.
5510004983711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 44.
Adding to 5510004983711 its reverse (1173894000155), we get a palindrome (6683898983866).
The spelling of 5510004983711 in words is "five trillion, five hundred ten billion, four million, nine hundred eighty-three thousand, seven hundred eleven".
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