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55100325536653 is a prime number
BaseRepresentation
bin11001000011101000010110…
…10101001010001110001101
321020002112120102110201010211
430201310023111022032031
524210230431314133103
6313104423510202421
714414603301240235
oct1441641325121615
9236075512421124
1055100325536653
1116613a0a337201
12621a98b653411
132498c27895cc7
14d86c27350cc5
15658444e7136d
hex321d0b54a38d

55100325536653 has 2 divisors, whose sum is σ = 55100325536654. Its totient is φ = 55100325536652.

The previous prime is 55100325536611. The next prime is 55100325536693. The reversal of 55100325536653 is 35663552300155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28254891074089 + 26845434462564 = 5315533^2 + 5181258^2 .

It is a cyclic number.

It is not a de Polignac number, because 55100325536653 - 213 = 55100325528461 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55100325536597 and 55100325536606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55100325536693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27550162768326 + 27550162768327.

It is an arithmetic number, because the mean of its divisors is an integer number (27550162768327).

Almost surely, 255100325536653 is an apocalyptic number.

It is an amenable number.

55100325536653 is a deficient number, since it is larger than the sum of its proper divisors (1).

55100325536653 is an equidigital number, since it uses as much as digits as its factorization.

55100325536653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6075000, while the sum is 49.

The spelling of 55100325536653 in words is "fifty-five trillion, one hundred billion, three hundred twenty-five million, five hundred thirty-six thousand, six hundred fifty-three".