Base | Representation |
---|---|
bin | 11001000011101000010111… |
… | …01010101000011111011101 |
3 | 21020002112120211001200200121 |
4 | 30201310023222220133131 |
5 | 24210230434234300121 |
6 | 313104424230554541 |
7 | 14414603400133315 |
oct | 1441641352503735 |
9 | 236075524050617 |
10 | 55100331165661 |
11 | 16613a12531381 |
12 | 621a991508a51 |
13 | 2498c28ab7192 |
14 | d86c27db8445 |
15 | 6584456d4141 |
hex | 321d0baa87dd |
55100331165661 has 2 divisors, whose sum is σ = 55100331165662. Its totient is φ = 55100331165660.
The previous prime is 55100331165653. The next prime is 55100331165673. The reversal of 55100331165661 is 16656113300155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53649486825561 + 1450844340100 = 7324581^2 + 1204510^2 .
It is a cyclic number.
It is not a de Polignac number, because 55100331165661 - 23 = 55100331165653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55100331165461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27550165582830 + 27550165582831.
It is an arithmetic number, because the mean of its divisors is an integer number (27550165582831).
Almost surely, 255100331165661 is an apocalyptic number.
It is an amenable number.
55100331165661 is a deficient number, since it is larger than the sum of its proper divisors (1).
55100331165661 is an equidigital number, since it uses as much as digits as its factorization.
55100331165661 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 43.
The spelling of 55100331165661 in words is "fifty-five trillion, one hundred billion, three hundred thirty-one million, one hundred sixty-five thousand, six hundred sixty-one".
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