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551011133501 = 4312814212407
BaseRepresentation
bin10000000010010101101…
…00101010100000111101
31221200020220122210021022
420001022310222200331
533011432322233001
61101044144513525
754544366233233
oct10011264524075
91850226583238
10551011133501
111a2756469074
128a95861b8a5
133cc6352543a
141c951d5c953
15e4ee15811b
hex804ad2a83d

551011133501 has 4 divisors (see below), whose sum is σ = 563825345952. Its totient is φ = 538196921052.

The previous prime is 551011133447. The next prime is 551011133509. The reversal of 551011133501 is 105331110155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 551011133501 - 226 = 550944024637 is a prime.

It is a super-2 number, since 2×5510111335012 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (551011133509) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6407106161 + ... + 6407106246.

It is an arithmetic number, because the mean of its divisors is an integer number (140956336488).

Almost surely, 2551011133501 is an apocalyptic number.

It is an amenable number.

551011133501 is a deficient number, since it is larger than the sum of its proper divisors (12814212451).

551011133501 is a wasteful number, since it uses less digits than its factorization.

551011133501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12814212450.

The product of its (nonzero) digits is 1125, while the sum is 26.

Adding to 551011133501 its reverse (105331110155), we get a palindrome (656342243656).

The spelling of 551011133501 in words is "five hundred fifty-one billion, eleven million, one hundred thirty-three thousand, five hundred one".

Divisors: 1 43 12814212407 551011133501