Base | Representation |
---|---|
bin | 10000000010010101101… |
… | …00101010100001000101 |
3 | 1221200020220122210021121 |
4 | 20001022310222201011 |
5 | 33011432322233014 |
6 | 1101044144513541 |
7 | 54544366233244 |
oct | 10011264524105 |
9 | 1850226583247 |
10 | 551011133509 |
11 | 1a2756469081 |
12 | 8a95861b8b1 |
13 | 3cc63525445 |
14 | 1c951d5c95b |
15 | e4ee158124 |
hex | 804ad2a845 |
551011133509 has 2 divisors, whose sum is σ = 551011133510. Its totient is φ = 551011133508.
The previous prime is 551011133447. The next prime is 551011133513. The reversal of 551011133509 is 905331110155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 479376216900 + 71634916609 = 692370^2 + 267647^2 .
It is a cyclic number.
It is not a de Polignac number, because 551011133509 - 219 = 551010609221 is a prime.
It is a super-2 number, since 2×5510111335092 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551011133539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275505566754 + 275505566755.
It is an arithmetic number, because the mean of its divisors is an integer number (275505566755).
Almost surely, 2551011133509 is an apocalyptic number.
It is an amenable number.
551011133509 is a deficient number, since it is larger than the sum of its proper divisors (1).
551011133509 is an equidigital number, since it uses as much as digits as its factorization.
551011133509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10125, while the sum is 34.
The spelling of 551011133509 in words is "five hundred fifty-one billion, eleven million, one hundred thirty-three thousand, five hundred nine".
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