Base | Representation |
---|---|
bin | 10000000010010101101… |
… | …00101010100000111110 |
3 | 1221200020220122210021100 |
4 | 20001022310222200332 |
5 | 33011432322233002 |
6 | 1101044144513530 |
7 | 54544366233234 |
oct | 10011264524076 |
9 | 1850226583240 |
10 | 551011133502 |
11 | 1a2756469075 |
12 | 8a95861b8a6 |
13 | 3cc6352543b |
14 | 1c951d5c954 |
15 | e4ee15811c |
hex | 804ad2a83e |
551011133502 has 24 divisors (see below), whose sum is σ = 1193873493384. Its totient is φ = 183667910544.
The previous prime is 551011133447. The next prime is 551011133509. The reversal of 551011133502 is 205331110155.
551011133502 is a `hidden beast` number, since 5 + 5 + 10 + 11 + 133 + 502 = 666.
It is a super-2 number, since 2×5510111335022 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (551011133509) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1600233 + ... + 1913835.
It is an arithmetic number, because the mean of its divisors is an integer number (49744728891).
Almost surely, 2551011133502 is an apocalyptic number.
551011133502 is an abundant number, since it is smaller than the sum of its proper divisors (642862359882).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
551011133502 is a wasteful number, since it uses less digits than its factorization.
551011133502 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 411224 (or 411221 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
Adding to 551011133502 its reverse (205331110155), we get a palindrome (756342243657).
The spelling of 551011133502 in words is "five hundred fifty-one billion, eleven million, one hundred thirty-three thousand, five hundred two".
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