Base | Representation |
---|---|
bin | 101000000101111001000… |
… | …1111000110111001011011 |
3 | 201111202211011020021221010 |
4 | 1100023302033012321123 |
5 | 1210234403300321110 |
6 | 15415205000545003 |
7 | 1106046123140541 |
oct | 120136217067133 |
9 | 21452734207833 |
10 | 5510212120155 |
11 | 18349600aaa86 |
12 | 74babaa82163 |
13 | 30c7c2b3b392 |
14 | 1509a4d87d91 |
15 | 984eeb63020 |
hex | 502f23c6e5b |
5510212120155 has 32 divisors (see below), whose sum is σ = 9335782738944. Its totient is φ = 2765662946816.
The previous prime is 5510212120117. The next prime is 5510212120159.
5510212120155 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 5510212120155 - 27 = 5510212120027 is a prime.
It is a super-3 number, since 3×55102121201553 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5510212120159) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1905982 + ... + 3827948.
It is an arithmetic number, because the mean of its divisors is an integer number (291743210592).
Almost surely, 25510212120155 is an apocalyptic number.
5510212120155 is a deficient number, since it is larger than the sum of its proper divisors (3825570618789).
5510212120155 is a wasteful number, since it uses less digits than its factorization.
5510212120155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1933235.
The product of its (nonzero) digits is 5000, while the sum is 30.
The spelling of 5510212120155 in words is "five trillion, five hundred ten billion, two hundred twelve million, one hundred twenty thousand, one hundred fifty-five".
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