Base | Representation |
---|---|
bin | 110011010100010110… |
… | …110010011101100001 |
3 | 12021020011210110122021 |
4 | 303110112302131201 |
5 | 1400322200214301 |
6 | 41151430341441 |
7 | 3660326154142 |
oct | 632426623541 |
9 | 167204713567 |
10 | 55102351201 |
11 | 21406928027 |
12 | a8197ba881 |
13 | 5271b86351 |
14 | 294a235ac9 |
15 | 16777b78a1 |
hex | cd45b2761 |
55102351201 has 2 divisors, whose sum is σ = 55102351202. Its totient is φ = 55102351200.
The previous prime is 55102351189. The next prime is 55102351207. The reversal of 55102351201 is 10215320155.
55102351201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41118106176 + 13984245025 = 202776^2 + 118255^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55102351201 is a prime.
It is a super-2 number, since 2×551023512012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55102351207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27551175600 + 27551175601.
It is an arithmetic number, because the mean of its divisors is an integer number (27551175601).
Almost surely, 255102351201 is an apocalyptic number.
It is an amenable number.
55102351201 is a deficient number, since it is larger than the sum of its proper divisors (1).
55102351201 is an equidigital number, since it uses as much as digits as its factorization.
55102351201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 55102351201 its reverse (10215320155), we get a palindrome (65317671356).
The spelling of 55102351201 in words is "fifty-five billion, one hundred two million, three hundred fifty-one thousand, two hundred one".
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