Base | Representation |
---|---|
bin | 101000000110000001100… |
… | …0010001100000100100011 |
3 | 201111210112210112112111211 |
4 | 1100030003002030010203 |
5 | 1210240442422234042 |
6 | 15415252545250551 |
7 | 1106056114464631 |
oct | 120140302140443 |
9 | 21453483475454 |
10 | 5510493946147 |
11 | 1834a951a1023 |
12 | 74bb79333a57 |
13 | 30c839344c18 |
14 | 1509d058a351 |
15 | 98519782017 |
hex | 5030308c123 |
5510493946147 has 2 divisors, whose sum is σ = 5510493946148. Its totient is φ = 5510493946146.
The previous prime is 5510493945997. The next prime is 5510493946151. The reversal of 5510493946147 is 7416493940155.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5510493946147 is a prime.
It is a super-2 number, since 2×55104939461472 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5510493946091 and 5510493946100.
It is not a weakly prime, because it can be changed into another prime (5510493976147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2755246973073 + 2755246973074.
It is an arithmetic number, because the mean of its divisors is an integer number (2755246973074).
Almost surely, 25510493946147 is an apocalyptic number.
5510493946147 is a deficient number, since it is larger than the sum of its proper divisors (1).
5510493946147 is an equidigital number, since it uses as much as digits as its factorization.
5510493946147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16329600, while the sum is 58.
The spelling of 5510493946147 in words is "five trillion, five hundred ten billion, four hundred ninety-three million, nine hundred forty-six thousand, one hundred forty-seven".
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