Base | Representation |
---|---|
bin | 11001000011111011011111… |
… | …01111010101100101000111 |
3 | 21020010112002110210022210111 |
4 | 30201331233233111211013 |
5 | 24210413002103230421 |
6 | 313113243220533451 |
7 | 14415416021222446 |
oct | 1441755757254507 |
9 | 236115073708714 |
10 | 55110600055111 |
11 | 16618302000a77 |
12 | 6220978551287 |
13 | 2499ba43cbb23 |
14 | d8751db32d5d |
15 | 658846ea7ee1 |
hex | 321f6fbd5947 |
55110600055111 has 2 divisors, whose sum is σ = 55110600055112. Its totient is φ = 55110600055110.
The previous prime is 55110600055087. The next prime is 55110600055151. The reversal of 55110600055111 is 11155000601155.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55110600055111 - 29 = 55110600054599 is a prime.
It is a super-3 number, since 3×551106000551113 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55110600055151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27555300027555 + 27555300027556.
It is an arithmetic number, because the mean of its divisors is an integer number (27555300027556).
Almost surely, 255110600055111 is an apocalyptic number.
55110600055111 is a deficient number, since it is larger than the sum of its proper divisors (1).
55110600055111 is an equidigital number, since it uses as much as digits as its factorization.
55110600055111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3750, while the sum is 31.
Adding to 55110600055111 its reverse (11155000601155), we get a palindrome (66265600656266).
The spelling of 55110600055111 in words is "fifty-five trillion, one hundred ten billion, six hundred million, fifty-five thousand, one hundred eleven".
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