Base | Representation |
---|---|
bin | 11001000011111100101101… |
… | …01010001000010000011111 |
3 | 21020010120202222102102111201 |
4 | 30201332112222020100133 |
5 | 24210420321232014442 |
6 | 313113432103500331 |
7 | 14415441140166502 |
oct | 1441762652102037 |
9 | 236116688372451 |
10 | 55111253001247 |
11 | 16618607632083 |
12 | 6220b1b1576a7 |
13 | 2499c79774aa1 |
14 | d8758273d139 |
15 | 6588844837b7 |
hex | 321f96a8841f |
55111253001247 has 2 divisors, whose sum is σ = 55111253001248. Its totient is φ = 55111253001246.
The previous prime is 55111253001239. The next prime is 55111253001391. The reversal of 55111253001247 is 74210035211155.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55111253001247 - 23 = 55111253001239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55111253001227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27555626500623 + 27555626500624.
It is an arithmetic number, because the mean of its divisors is an integer number (27555626500624).
Almost surely, 255111253001247 is an apocalyptic number.
55111253001247 is a deficient number, since it is larger than the sum of its proper divisors (1).
55111253001247 is an equidigital number, since it uses as much as digits as its factorization.
55111253001247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42000, while the sum is 37.
The spelling of 55111253001247 in words is "fifty-five trillion, one hundred eleven billion, two hundred fifty-three million, one thousand, two hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •