55111520131403 has 2 divisors, whose sum is σ = 55111520131404. Its totient is φ = 55111520131402.

The previous prime is 55111520131397. The next prime is 55111520131469. The reversal of 55111520131403 is 30413102511155.

55111520131403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55111520131403 - 2¹⁴ = 55111520115019 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 55111520131403.

It is not a weakly prime, because it can be changed into another prime (55111520131483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27555760065701 + 27555760065702.

It is an arithmetic number, because the mean of its divisors is an integer number (27555760065702).

Almost surely, 2^{55111520131403} is an apocalyptic number.

55111520131403 is a deficient number, since it is larger than the sum of its proper divisors (1).

55111520131403 is an equidigital number, since it uses as much as digits as its factorization.

55111520131403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9000, while the sum is 32.

Adding to 55111520131403 its reverse (30413102511155), we get a palindrome (85524622642558).

The spelling of 55111520131403 in words is "fifty-five trillion, one hundred eleven billion, five hundred twenty million, one hundred thirty-one thousand, four hundred three".