Base | Representation |
---|---|
bin | 1010010000111111… |
… | …00100000101001111 |
3 | 112020002022000122101 |
4 | 11020133210011033 |
5 | 42241331413403 |
6 | 2310512055531 |
7 | 253400302462 |
oct | 51037440517 |
9 | 15202260571 |
10 | 5511201103 |
11 | 2378a24a61 |
12 | 10998345a7 |
13 | 69aa36155 |
14 | 3a3d312d9 |
15 | 223c8371d |
hex | 1487e414f |
5511201103 has 2 divisors, whose sum is σ = 5511201104. Its totient is φ = 5511201102.
The previous prime is 5511201077. The next prime is 5511201127. The reversal of 5511201103 is 3011021155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5511201103 - 25 = 5511201071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5511201193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2755600551 + 2755600552.
It is an arithmetic number, because the mean of its divisors is an integer number (2755600552).
Almost surely, 25511201103 is an apocalyptic number.
5511201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5511201103 is an equidigital number, since it uses as much as digits as its factorization.
5511201103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 19.
The square root of 5511201103 is about 74237.4642818570. The cubic root of 5511201103 is about 1766.3716519409.
Adding to 5511201103 its reverse (3011021155), we get a palindrome (8522222258).
The spelling of 5511201103 in words is "five billion, five hundred eleven million, two hundred one thousand, one hundred three".
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