Search a number
-
+
551123048701 is a prime number
BaseRepresentation
bin10000000010100010111…
…11100101100011111101
31221200112201020200001201
420001101133211203331
533012200000024301
61101103223335501
754550225422511
oct10012137454375
91850481220051
10551123048701
111a2803658675
128a989bb1591
133cc8077b454
141c962b72141
15e508db3201
hex80517e58fd

551123048701 has 2 divisors, whose sum is σ = 551123048702. Its totient is φ = 551123048700.

The previous prime is 551123048633. The next prime is 551123048713. The reversal of 551123048701 is 107840321155.

551123048701 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 395516467801 + 155606580900 = 628901^2 + 394470^2 .

It is a cyclic number.

It is not a de Polignac number, because 551123048701 - 229 = 550586177789 is a prime.

It is a super-2 number, since 2×5511230487012 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551123048761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275561524350 + 275561524351.

It is an arithmetic number, because the mean of its divisors is an integer number (275561524351).

Almost surely, 2551123048701 is an apocalyptic number.

It is an amenable number.

551123048701 is a deficient number, since it is larger than the sum of its proper divisors (1).

551123048701 is an equidigital number, since it uses as much as digits as its factorization.

551123048701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33600, while the sum is 37.

Adding to 551123048701 its reverse (107840321155), we get a palindrome (658963369856).

The spelling of 551123048701 in words is "five hundred fifty-one billion, one hundred twenty-three million, forty-eight thousand, seven hundred one".