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55112811773 is a prime number
BaseRepresentation
bin110011010100111110…
…101100010011111101
312021020220110220211212
4303110332230103331
51400332334434043
641152442454205
73660514112345
oct632476542375
9167226426755
1055112811773
1121411822228
12a821204365
1352740a9736
14294b799d25
151678682018
hexcd4fac4fd

55112811773 has 2 divisors, whose sum is σ = 55112811774. Its totient is φ = 55112811772.

The previous prime is 55112811709. The next prime is 55112811841. The reversal of 55112811773 is 37711821155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36025178809 + 19087632964 = 189803^2 + 138158^2 .

It is a cyclic number.

It is not a de Polignac number, because 55112811773 - 26 = 55112811709 is a prime.

It is a super-2 number, since 2×551128117732 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55112811773.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55112811673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27556405886 + 27556405887.

It is an arithmetic number, because the mean of its divisors is an integer number (27556405887).

Almost surely, 255112811773 is an apocalyptic number.

It is an amenable number.

55112811773 is a deficient number, since it is larger than the sum of its proper divisors (1).

55112811773 is an equidigital number, since it uses as much as digits as its factorization.

55112811773 is an evil number, because the sum of its binary digits is even.

The product of its digits is 58800, while the sum is 41.

The spelling of 55112811773 in words is "fifty-five billion, one hundred twelve million, eight hundred eleven thousand, seven hundred seventy-three".