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5511433141 is a prime number
BaseRepresentation
bin1010010001000000…
…11100101110110101
3112020002201210221101
411020200130232311
542241411330031
62310521050101
7253402260124
oct51040345665
915202653841
105511433141
112379073325
121099926931
1369aab7956
143a3d91abb
15223ccc361
hex14881cbb5

5511433141 has 2 divisors, whose sum is σ = 5511433142. Its totient is φ = 5511433140.

The previous prime is 5511433129. The next prime is 5511433219. The reversal of 5511433141 is 1413341155.

5511433141 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5257700100 + 253733041 = 72510^2 + 15929^2 .

It is a cyclic number.

It is not a de Polignac number, because 5511433141 - 221 = 5509335989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5511431141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2755716570 + 2755716571.

It is an arithmetic number, because the mean of its divisors is an integer number (2755716571).

Almost surely, 25511433141 is an apocalyptic number.

It is an amenable number.

5511433141 is a deficient number, since it is larger than the sum of its proper divisors (1).

5511433141 is an equidigital number, since it uses as much as digits as its factorization.

5511433141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3600, while the sum is 28.

The square root of 5511433141 is about 74239.0270747132. The cubic root of 5511433141 is about 1766.3964414308.

Adding to 5511433141 its reverse (1413341155), we get a palindrome (6924774296).

The spelling of 5511433141 in words is "five billion, five hundred eleven million, four hundred thirty-three thousand, one hundred forty-one".