Base | Representation |
---|---|
bin | 110011010101001110… |
… | …110111011000000001 |
3 | 12021021012110022111211 |
4 | 303111032313120001 |
5 | 1400334431121033 |
6 | 41153113410121 |
7 | 3660565130635 |
oct | 632516673001 |
9 | 167235408454 |
10 | 55117051393 |
11 | 21414158548 |
12 | a822709941 |
13 | 5274c323a1 |
14 | 294c180dc5 |
15 | 1678c1d2cd |
hex | cd53b7601 |
55117051393 has 2 divisors, whose sum is σ = 55117051394. Its totient is φ = 55117051392.
The previous prime is 55117051343. The next prime is 55117051411. The reversal of 55117051393 is 39315071155.
It is a happy number.
55117051393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34259048464 + 20858002929 = 185092^2 + 144423^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55117051393 is a prime.
It is not a weakly prime, because it can be changed into another prime (55117051343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27558525696 + 27558525697.
It is an arithmetic number, because the mean of its divisors is an integer number (27558525697).
Almost surely, 255117051393 is an apocalyptic number.
It is an amenable number.
55117051393 is a deficient number, since it is larger than the sum of its proper divisors (1).
55117051393 is an equidigital number, since it uses as much as digits as its factorization.
55117051393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70875, while the sum is 40.
The spelling of 55117051393 in words is "fifty-five billion, one hundred seventeen million, fifty-one thousand, three hundred ninety-three".
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