Base | Representation |
---|---|
bin | 101000000110110010011… |
… | …0100100111100110101001 |
3 | 201111221210010122011020102 |
4 | 1100031210310213212221 |
5 | 1210302322421243243 |
6 | 15420123433235145 |
7 | 1106144555443145 |
oct | 120154464474651 |
9 | 21457703564212 |
10 | 5512134556073 |
11 | 183575728a5a2 |
12 | 750356862ab5 |
13 | 30ca3b1c9022 |
14 | 150b08412225 |
15 | 985b38039b8 |
hex | 50364d279a9 |
5512134556073 has 2 divisors, whose sum is σ = 5512134556074. Its totient is φ = 5512134556072.
The previous prime is 5512134555959. The next prime is 5512134556079. The reversal of 5512134556073 is 3706554312155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5502528988009 + 9605568064 = 2345747^2 + 98008^2 .
It is a cyclic number.
It is not a de Polignac number, because 5512134556073 - 218 = 5512134293929 is a prime.
It is not a weakly prime, because it can be changed into another prime (5512134556079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756067278036 + 2756067278037.
It is an arithmetic number, because the mean of its divisors is an integer number (2756067278037).
Almost surely, 25512134556073 is an apocalyptic number.
It is an amenable number.
5512134556073 is a deficient number, since it is larger than the sum of its proper divisors (1).
5512134556073 is an equidigital number, since it uses as much as digits as its factorization.
5512134556073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1890000, while the sum is 47.
The spelling of 5512134556073 in words is "five trillion, five hundred twelve billion, one hundred thirty-four million, five hundred fifty-six thousand, seventy-three".
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