Base | Representation |
---|---|
bin | 11001000100001111110010… |
… | …11101111001101110011101 |
3 | 21020011120020011020012010001 |
4 | 30202013321131321232131 |
5 | 24211102313133044343 |
6 | 313122245015014301 |
7 | 14416253113034335 |
oct | 1442077135715635 |
9 | 236146204205101 |
10 | 55121500674973 |
11 | 16621996131017 |
12 | 6222abb06a391 |
13 | 249ac2086bb55 |
14 | d87c757340c5 |
15 | 658c83e6644d |
hex | 3221f9779b9d |
55121500674973 has 2 divisors, whose sum is σ = 55121500674974. Its totient is φ = 55121500674972.
The previous prime is 55121500674953. The next prime is 55121500675067. The reversal of 55121500674973 is 37947600512155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50576532911524 + 4544967763449 = 7111718^2 + 2131893^2 .
It is a cyclic number.
It is not a de Polignac number, because 55121500674973 - 225 = 55121467120541 is a prime.
It is a super-2 number, since 2×551215006749732 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55121500674943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27560750337486 + 27560750337487.
It is an arithmetic number, because the mean of its divisors is an integer number (27560750337487).
Almost surely, 255121500674973 is an apocalyptic number.
It is an amenable number.
55121500674973 is a deficient number, since it is larger than the sum of its proper divisors (1).
55121500674973 is an equidigital number, since it uses as much as digits as its factorization.
55121500674973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7938000, while the sum is 55.
The spelling of 55121500674973 in words is "fifty-five trillion, one hundred twenty-one billion, five hundred million, six hundred seventy-four thousand, nine hundred seventy-three".
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