Search a number
-
+
551215420031 is a prime number
BaseRepresentation
bin10000000010101101111…
…11111101001001111111
31221200210011001121201002
420001112333331021333
533012342121420111
61101120323240515
754552426522623
oct10012677751177
91850704047632
10551215420031
111a2850809611
128a9b4b1913b
133cc96950843
141c971139183
15e51205c63b
hex8056ffd27f

551215420031 has 2 divisors, whose sum is σ = 551215420032. Its totient is φ = 551215420030.

The previous prime is 551215419943. The next prime is 551215420061. The reversal of 551215420031 is 130024512155.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 551215420031 - 238 = 276337513087 is a prime.

It is a super-2 number, since 2×5512154200312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 551215419976 and 551215420003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551215420061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275607710015 + 275607710016.

It is an arithmetic number, because the mean of its divisors is an integer number (275607710016).

Almost surely, 2551215420031 is an apocalyptic number.

551215420031 is a deficient number, since it is larger than the sum of its proper divisors (1).

551215420031 is an equidigital number, since it uses as much as digits as its factorization.

551215420031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6000, while the sum is 29.

Adding to 551215420031 its reverse (130024512155), we get a palindrome (681239932186).

The spelling of 551215420031 in words is "five hundred fifty-one billion, two hundred fifteen million, four hundred twenty thousand, thirty-one".