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55122506533 is a prime number
BaseRepresentation
bin110011010101100011…
…101011001100100101
312021021120201110120001
4303111203223030211
51400342330202113
641153430341301
73660662401063
oct632543531445
9167246643501
1055122506533
1121417244026
12a8244ba831
1352760c2393
14294cba1033
1516794497dd
hexcd58eb325

55122506533 has 2 divisors, whose sum is σ = 55122506534. Its totient is φ = 55122506532.

The previous prime is 55122506479. The next prime is 55122506557. The reversal of 55122506533 is 33560522155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50347281924 + 4775224609 = 224382^2 + 69103^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55122506533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55122506492 and 55122506501.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55122506573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27561253266 + 27561253267.

It is an arithmetic number, because the mean of its divisors is an integer number (27561253267).

Almost surely, 255122506533 is an apocalyptic number.

It is an amenable number.

55122506533 is a deficient number, since it is larger than the sum of its proper divisors (1).

55122506533 is an equidigital number, since it uses as much as digits as its factorization.

55122506533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 55122506533 in words is "fifty-five billion, one hundred twenty-two million, five hundred six thousand, five hundred thirty-three".