Base | Representation |
---|---|
bin | 10000000010110001010… |
… | …10111001101010011111 |
3 | 1221200212002210221122021 |
4 | 20001120222321222133 |
5 | 33012421311031020 |
6 | 1101123204201011 |
7 | 54553220025622 |
oct | 10013052715237 |
9 | 1850762727567 |
10 | 551243455135 |
11 | 1a286561781a |
12 | 8aa02399167 |
13 | 3cc9c6b8369 |
14 | 1c974b55db9 |
15 | e5147491aa |
hex | 8058ab9a9f |
551243455135 has 32 divisors (see below), whose sum is σ = 698413363200. Its totient is φ = 416861668608.
The previous prime is 551243455123. The next prime is 551243455201. The reversal of 551243455135 is 531554342155.
It is a cyclic number.
It is not a de Polignac number, because 551243455135 - 217 = 551243324063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 551243455091 and 551243455100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3434916 + ... + 3591814.
It is an arithmetic number, because the mean of its divisors is an integer number (21825417600).
Almost surely, 2551243455135 is an apocalyptic number.
551243455135 is a deficient number, since it is larger than the sum of its proper divisors (147169908065).
551243455135 is a wasteful number, since it uses less digits than its factorization.
551243455135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157287.
The product of its digits is 900000, while the sum is 43.
The spelling of 551243455135 in words is "five hundred fifty-one billion, two hundred forty-three million, four hundred fifty-five thousand, one hundred thirty-five".
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