Base | Representation |
---|---|
bin | 10000000010110010001… |
… | …11110000101011001101 |
3 | 1221200212122001022100201 |
4 | 20001121013300223031 |
5 | 33012430230123433 |
6 | 1101124034253501 |
7 | 54553341235225 |
oct | 10013107605315 |
9 | 1850778038321 |
10 | 551251020493 |
11 | 1a2869914788 |
12 | 8aa04a27291 |
13 | 3cca11369c4 |
14 | 1c975b65085 |
15 | e515240a7d |
hex | 80591f0acd |
551251020493 has 2 divisors, whose sum is σ = 551251020494. Its totient is φ = 551251020492.
The previous prime is 551251020469. The next prime is 551251020581. The reversal of 551251020493 is 394020152155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 352725524649 + 198525495844 = 593907^2 + 445562^2 .
It is a cyclic number.
It is not a de Polignac number, because 551251020493 - 25 = 551251020461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551251020413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275625510246 + 275625510247.
It is an arithmetic number, because the mean of its divisors is an integer number (275625510247).
Almost surely, 2551251020493 is an apocalyptic number.
It is an amenable number.
551251020493 is a deficient number, since it is larger than the sum of its proper divisors (1).
551251020493 is an equidigital number, since it uses as much as digits as its factorization.
551251020493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 551251020493 in words is "five hundred fifty-one billion, two hundred fifty-one million, twenty thousand, four hundred ninety-three".
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